1) What is the minimum possible number of ones in the subnet masks of two nodes with IP addresses 45.218.13.76
1) What is the minimum possible number of ones in the subnet masks of two nodes with IP addresses 45.218.13.76 and 45.218.13.55, located in different subnets?
2) What is the minimum possible number of ones in the subnet masks of two nodes with IP addresses 145.207.153.178 and 145.207.153.165, located in different subnets?
3) Given a node with an IP address of 115.53.128.88 and a subnet address of 115.53.128.0, how many different possible values are there for the third byte from the left?
25.11.2023 14:11
Объяснение: Subnet masks and IP addresses are used in computer networks to divide the network into smaller subnets. A subnet mask is a 32-bit number that determines the network and subnet portion of the IP address. It is represented using four octets separated by periods, with each octet ranging from 0 to 255.
In order to find the minimum possible number of ones in the subnet masks of two nodes with different IP addresses, we need to compare the binary representation of the IP addresses.
For the first question, the IP addresses are 45.218.13.76 and 45.218.13.55. The binary representation for both IP addresses is:
45.218.13.76 = 00101101.11011010.00001101.01001100
45.218.13.55 = 00101101.11011010.00001101.00110111
To find the minimum possible number of ones in the subnet masks, we compare the bits from left to right. The first different bit in the binary representation of the two IP addresses is the eighth bit. So, the subnet mask would have a minimum of 8 ones.
Similarly, for the second question, the IP addresses are 145.207.153.178 and 145.207.153.165. The binary representation for both IP addresses is:
145.207.153.178 = 10010001.11001111.10011001.10110010
145.207.153.165 = 10010001.11001111.10011001.10100101
Again, the first different bit in the binary representation is the eighth bit. So, the subnet mask would have a minimum of 8 ones.
For the third question, the IP address is 115.53.128.88 and the subnet address is 115.53.128.0. The binary representation for both IP addresses is:
115.53.128.88 = 01110011.00110101.10000000.01011000
115.53.128.0 = 01110011.00110101.10000000.00000000
The subnet mask for this IP address would have a minimum of 24 ones, since the first 24 bits are the same for both IP addresses. Therefore, the number of different possible values for the third byte from the left is 2^8 - 1 = 255.
Например:
1) IP addresses: 45.218.13.76, 45.218.13.55
- Binary representation: 00101101.11011010.00001101.01001100, 00101101.11011010.00001101.00110111
- Minimum number of ones in subnet masks: 8
2) IP addresses: 145.207.153.178, 145.207.153.165
- Binary representation: 10010001.11001111.10011001.10110010, 10010001.11001111.10011001.10100101
- Minimum number of ones in subnet masks: 8
3) IP address: 115.53.128.88, Subnet address: 115.53.128.0
- Binary representation: 01110011.00110101.10000000.01011000, 01110011.00110101.10000000.00000000
- Minimum number of ones in subnet masks: 24
- Different possible values for the third byte from the left: 255
Совет: To understand subnet masks and IP addresses better, it"s important to be familiar with binary representation and how to convert IP addresses to binary. You can practice converting IP addresses to binary and vice versa to improve your understanding. Additionally, studying the concept of subnetting and how it works in computer networks will help you grasp the relationship between IP addresses and subnet masks.
Задание: Given the IP addresses 192.168.1.23 and 192.168.1.45, what is the minimum possible number of ones in the subnet masks of two nodes located in different subnets?